求函数y=
题型: 解答题 难度: 一般
求函数y=
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lg
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答案
依题意,令lg
| x |
| x2-7x+12 |
即lg
| x |
| x2-7x+12 |
于是有??
| x |
| x2-7x+12 |
| x |
| x2-7x+12 |
| x2-8x-12 |
| x2-7x+12 |
| (x-2)(x-6) |
| (x-3)(x-4) |
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|
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评论 (0)
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lg
|
| x |
| x2-7x+12 |
| x |
| x2-7x+12 |
| x |
| x2-7x+12 |
| x |
| x2-7x+12 |
| x2-8x-12 |
| x2-7x+12 |
| (x-2)(x-6) |
| (x-3)(x-4) |
|
|
|